What kind of code I should use on C programing that allows the user to type a certain letter to terminate the program and does not terminate it until it is the same letter the programmer asks.?
C code that terminates the program
The following code snippet asks for a character which is known for exit. and then enters a loop where it asks for characters one by one and checks for necessary exit value. If found, it exits.
#include<stdio.h>Â
#include<conio.h>
void main(){
char exitchar,newchar;
printf("Enter the character for exit.");
scanf("%c",exitchar); Â Â Â //The character to exit is given as input
while ((newchar=getch())!=exitchar){ Â Â //getch() accepts a character and first places in newchar then checks for exit.
printf("%c",newchar); Â //print on screen
}
}
You may write the equivalent codeÂ
void main(){
char exitchar,newchar;
printf("Enter the character for exit.");
scanf("%c",exitchar); Â Â Â //The character to exit is given as input
while (1){ Â Â Â
newchar=getch();
If (newchar==exitchar)
return(0); Â Â Â //If the exitcharacter is found.
else
printf("%c",newchar); Â //print on screen
}
}
C code that terminates the program
Hello Ulysses Arredonto,
These are the working snippets for your query which shows the requirements you desire.
Try these and sort your program as you want.
#include<conio.h>
#include<stdio.h>
void main(void) {
   char e,n;
   printf ("Enter the character for exit: ");
   scanf ("%c", e);               // here e stores the exit character
   while ((n=getch())!=e) {         // the value is stored in n by getch() and checks for the exit value
       printf ("%c",n);            // values are shown on the screen until the e entered
   }
}
This is the code in C++ environment which might be helpful to you …
#include<conio.h>
#include<iostream.h>
#include<stdio.h>
void main(void) {
   char e,n;
   cout << "Enter the character for exit: ";
   cin >> e;               // here e stores the exit character
   while ((n=getch())!=e) {   // the value is stored in n by getch() and checks for the exit value
       cout << n;            // values are shown on the screen until the e entered
   }
}
Hope this will help you in your problem.
Thank you
Emon Asejo
C code that terminates the program
I tried this and it worked.
#include<conio.h>
#include<stdio.h>
void main(void) {
   char e,n;
   printf ("Enter the character for exit: ");
   scanf ("%c", e);               // here e stores the exit character
   while ((n=getch())!=e) {         // the value is stored in n by getch() and checks for the exit value
       printf ("%c",n);            // values are shown on the screen until the e entered
   }
}
This is the code in C++ environment which might be helpful to you …
#include<conio.h>
#include<iostream.h>
#include<stdio.h>
void main(void) {
   char e,n;
   cout << "Enter the character for exit: ";
   cin >> e;               // here e stores the exit character
   while ((n=getch())!=e) {   // the value is stored in n by getch() and checks for the exit value
       cout << n;            // values are shown on the screen until the e entered
   }
}
THANK YOU FOR THE HELP!!
