C problem with array s

C problem with array s

First let me know whether you have used the malloc or simply an array.

int A[30];

or

int *A=(int*)malloc(30*sizeof(int));

If you have used the first one, then

Recreate an array

int B[40];

Copy A[30] to B[30];

for(i=0;i<30;i++){ B[i]=A[i];}

Now use B[30] to B[39]. Reanme B to A

int * temp=A;

A=B;

free temp[];

If you have used the second one, then,

use Realloc()

A = ( int * ) realloc ( A , sizeof ( int ) * 40 );

You get a new array of size 40 with the previous elements intact.

If your requirement is Increasing Array, then try a linked List

struct node{

int A;

struct node *next;

};

struct node *head,*temp;

head = ( struct node * ) malloc ( sizeof ( struct node ));

head > A=0;

head > next=NULL;

for(i=1;i<30;i++){

traverse=head;

while(traverse->next!=NULL)

             traverse=traverse->next;

temp = ( struct node * ) malloc ( sizeof ( struct node ));}

temp->A=i;

temp->next=NULL;

traverse->next=temp;

//Now you have a linked list with 30 data;

//Print It

traverse=head;

while(traverse->next!=NULL){

             printf("%d",traverse->A);

             traverse=traverse->next;

}