Grooveshark error: invalid literalfor float(): iii

Asked By ELVIS EZAN 0 points N/A Posted on - 07/10/2011

Hi all,

I was working on a linear regression program, and when I try to convert the input file data to a float, I got this error.

Groove shark error: invalid literal for float (): iii. I'm using Windows XP SP2.

Any help?

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• Question Category: JavaScript

Answered By Santons 5 points N/A #81972

Grooveshark error: invalid literalfor float(): iii

 

This error is strange to the java script and it Looks like you are trying to convert a string to a float. If the string is E-135, the it is indeed an invalid value to be converted to a float. Perhaps you are chopping off a digit in the beginning of the string and it really ought to be something like 1E-135? That would be a valid float,

>>> float('1E-135')

1e-135

>>> float('E-135')

Traceback (most recent call last):

  File "<stdin>", line 1, in <module>

ValueError: invalid literal for float(): E-135

 

In fact, which number is E-135 supposed to represent? 1×10^-135?

 

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• Posted on - 07/14/2011
• Question Category: JavaScript