Asked By
Malina
20 points
N/A
Posted on - 08/12/2011
I need help i want to input a single character and print a message "It is a vowel" if it is a vowel otherwise print message
"It is a constant". By using if-else structure and OR operator only?
Input a single character and print a message
#include "stdafx.h"
#include <iostream>
#include <conio.h>
using namespace std;
int _tmain()
{
char v;
cout<<"Enter a character: ";
cin>>v;
if(v=='a'|| v=='e' || v=='i' || v=='o' || v=='u')
{
cout<<"It is vowel";
}
else
{
cout<<"It is constant";
}
getche();
}
Answered By
hitenny
0 points
N/A
#114149
Input a single character and print a message
It’s an easy task and just follow the instructions and code given below-
(Some comments are given for detail explanation of the lines)
#include <iostream>
using name space std;
int main()
{
char var; //declaring a character variable
cout<<""Enter a character value heren"";
cin>>var; //for reading or scanning the input for the character variable
// ternary operator ? : is used here if-else logic. ? represents if and : represents else
(var == 'a' || var == 'e' || var == 'i' || var == 'o' || var == 'u') ? cout<<""Vowel"" : cout<<""Constant"";
}
Input a single character and print a message
In C++ if-else is decision Operator. As in real life we have the option and in particular condition we do specific task. Same as IF-ELSE used in programming for taking decisions.
Syntax of if-else
void main()
{
if(condition)
{
// if condition is true pointer will run this part of the program
}
else
{
in false condition pointer will run this part.
}
}
your program
#include<iostream.h>
#include<conio.h>
void main()
{
char ch;
cout<<"Enter a character";
cin>>ch;
if(ch=='a'||ch=='e'||ch=='i'||ch=='o'||ch=='u'||ch=='A'||ch=='E'||ch=='I'||ch=='O'||ch=='U')
{
cout<<"its a vowel";
}
else
{
cout<<"its a consonant";
}
}
Here I have used OR operator in IF condition .by the use of OR(||) operator compiler run the true part of if condition if any of the given condition is true otherwise ELSE part would be run.
