Input a single character and print a message

Asked By Malina 20 points N/A Posted on - 08/12/2011

 I need help i want to input a single character and print a message "It is a vowel" if it is a vowel otherwise print message

"It is a constant". By using if-else structure and OR operator only?

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• Question Category: C++

Best Answer by Bryan Miguel

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Answered By Bryan Miguel 0 points N/A #114147

Input a single character and print a message

#include "stdafx.h"
#include <iostream>
#include <conio.h>
using namespace std;

int _tmain()
{
    char v;
    cout<<"Enter a character: ";
    cin>>v;

    if(v=='a'|| v=='e' || v=='i' || v=='o' || v=='u')
    {
        cout<<"It is vowel";
    }
    else
    {
        cout<<"It is constant";
    }
    getche();
}

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• Posted on - 08/12/2011
• Question Category: C++

Answered By hitenny 0 points N/A #114149

Input a single character and print a message

 

It’s an easy task and just follow the instructions and code given below-

 

(Some comments are given for detail explanation of the lines)

 

#include <iostream>

using name space std;

int main()

{

char var;        //declaring a character variable

cout<<""Enter a character value heren"";

cin>>var;                                 //for reading or scanning the input for the character variable

// ternary operator ? :  is used here if-else logic. ? represents if and : represents else

(var == 'a' || var == 'e' || var == 'i' || var == 'o' || var == 'u') ? cout<<""Vowel"" : cout<<""Constant"";

}

 

 

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• Posted on - 09/18/2011
• Question Category: C++

Answered By anamika-jain 0 points N/A #114151

Input a single character and print a message

In C++ if-else is decision Operator. As in real life we have the option and in particular condition we do specific task. Same as IF-ELSE used in programming for taking decisions.

Syntax of if-else

 

void main()

{

   if(condition)

   {

    // if condition is true pointer will run this part of the program

   }

 else

 {

   in false condition pointer will run this part.

 }

}

 your program

#include<iostream.h>

#include<conio.h>

void main()

{

  char ch;

 cout<<"Enter a character";

 cin>>ch;

 if(ch=='a'||ch=='e'||ch=='i'||ch=='o'||ch=='u'||ch=='A'||ch=='E'||ch=='I'||ch=='O'||ch=='U')

  {

    cout<<"its a vowel";

  }

 else

 {

   cout<<"its a consonant";

 }

}

Here I have used OR operator in IF condition .by the use of OR(||) operator compiler run the true part of if condition if any of the given condition is true otherwise ELSE part would be run.

 

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• Posted on - 09/28/2011
• Question Category: C++