Asked By
Dev_Raj
160 points
N/A
Posted on - 04/27/2011
Hi All
I need to write a program that will show the reverse order of an array’s elements.
What will be code for reversing the values of an array?
For example: if array = 5,8,12,19,25
Then program will show the out put as:
25,19,12,8,5
Any help would really be appreciated.
Answered By
Sahil
0 points
N/A
#88408
Reverse the values of an Array
All you need to do is to take these 5 numbers from the user and save them in an array. Firstly you will show the array in original order means with original index. After that you will show the array in reverse order, means you will start from the last index and one by one you will decrease the index instead of increasing.
Answered By
jAlbert
140 points
N/A
#88409
Reverse the values of an Array
How we can reverse the index of an array??????????????????
Answered By
Dev_Raj
160 points
N/A
#88411
Reverse the values of an Array
Dear Sahil
I need more help. I am confused about the index of an array. How I will calculate the index of an array and how I will reverse?
Waiting
Answered By
Sahil
0 points
N/A
#88412
Reverse the values of an Array
You will declare an array with index 5 as: num[5];
Then you will show the numbers of array as
for(i=0,i<5,i++)
cout<<num[i];
To show in reverse order you will write code as:
for(i=4,i>=0;i–)
cout<<num[i];
I don’t have C++ compiler at the moment. Try this with proper statements in compiler. If you don’t get the true result, please send me your code. So I can help you more.
Reverse the values of an Array
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr
int num[5],I;
for(i=0,i<5,i++)
{
Cout<<”enter the number”<<endl;
Cin>>num[i];
}
count<<”n the array in actual order”<<endl;
for(i=0,i<5,i++)
cout<<num[i];
count<<”n the array in reverse order”<<endl;
for(i=4,i>=0;i–)
cout<<num[i];
getch();
}
Answered By
Dev_Raj
160 points
N/A
#88414
Reverse the values of an Array
Thanks a lot Mark Jason
It really helps me out to understand fully the concept of array and arrays with indexing.
Regards